A pressure of $10 k P a$ acts on an area of $0.3 m^{2}$ . The force acting on the area will be ________.

300 N

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30 N

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3000 N

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3 N

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Solution

The correct option is C $3000 N$
$P r e s s u r e = \frac{F o r c e}{A r e a}$
$P r e s s u r e = 10 k P a$
$= 10 \times 1000 = 10000 P a$
$A r e a = 0.3 m^{2}$
$F o r c e = P r e s s u r e \times A r e a$
$F o r c e = 10000 \times 0.3 = 3000 N$

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