a pressure of 1000 pa,acts on a surface of area 15cm2 by a block if the area of contact with the surface becomes 10 cm2

Open in App

Solution

$p r e s s u r e = f o r c e / a r e a f o r c e = p r e s s u r e \times a r e a f o r c e = 1000 \times 15 \times 10^{- 4} = 1.5 N p r e s s u r e e x e r t e d b y t h e a r a e 10 c m^{2} i s g i v e n b y : P = 1.5 / 10 \times 10^{- 4} = 1500 p a s c a l$

Suggest Corrections

Similar questions

When a force of 5 N acts on a surface,it produces a pressure of 500 Pa.The area of surface then must be :
(a) $10 c m^{2}$ (b) $50 c m^{2}$ (c) $100 c m^{2}$ (d) $0.01 c m^{2}$

Q. Calculate the pressure exerted by a block of weight

500 N

if the surface area in contact is

2.5 c m^{2}

Statement 1: For the same load/force acting on two different surfaces, more pressure is developed on the surface with a smaller area.
Statement 2: Pressure is inversely proportional to the area of contact.

Find the pressure in pascal when a thrust of $100 k g f$ is acting on a surface of area $5 m^{2}$ .

Q. A

1000 N

thrust acting on a surface can exert a pressure of a million pascals. What will be the area (in

{cm}^{2}

) of the surface bearing the pressure?

Join BYJU'S Learning Program

a pressure of 1000 pa,acts on a surface of area 15cm2 by a block if the area of contact with the surface becomes 10 cm2

pressure = force / areaforce = pressure ×areaforce = 1000×15×10-4 = 1.5 Npressure exerted by the arae 10 cm2 is given by:P =1.5/10×10-4 = 1500 pascal

$p r e s s u r e = f o r c e / a r e a f o r c e = p r e s s u r e \times a r e a f o r c e = 1000 \times 15 \times 10^{- 4} = 1.5 N p r e s s u r e e x e r t e d b y t h e a r a e 10 c m^{2} i s g i v e n b y : P = 1.5 / 10 \times 10^{- 4} = 1500 p a s c a l$