A pressure of 200 Pa is acting on an area of $0.5 m^{2}$ . Find the thrust exerted on this area.

400 N

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200 N

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100 N

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50 N

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Solution

The correct option is C 100 N
Pressure (P) = 200 Pa
Area of contact $A = 0.5 m^{2}$
We have, $P r e s s u r e = \frac{T h r u s t}{A r e a}$
$∴ T h r u s t = P r e s s u r e \times A r e a$
$= 200 \times 0.5 = 100 N$

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