A primary alcohol, $C_{3} H_{8} O (A)$ on heating with sulphuric acid undergo dehydration to give an alkene, B. B, when reacted with $H C l$ , gave C, which on treatment with aqueous KOH gives compound $D (C_{3} H_{8} O)$ .
A and D are:

functional isomers

No worries! We‘ve got your back. Try BYJU‘S free classes today!

position isomers

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

chain isomers

No worries! We‘ve got your back. Try BYJU‘S free classes today!

stereoisomers.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C position isomers
$C_{3} H_{8} O (A) H_{2} S O_{4}, Δ ⟶ B (a l k e n e) H C l ⟶ C a q . K O H ⟶ D (C_{3} H_{8} O)$

Since A is primary alcohol, thus it can only be $C H_{3} C H_{2} C H_{2} O H$
upon dehydration it gives B as:

$C H_{3} C H_{2} C H_{2} O H H_{2} S O_{4}, Δ ⟶ C H_{3} C H = C H_{2}$

thus $B \Rightarrow C H_{3} C H = C H_{2}$

Alkene with HCl will undergo addition across double bond by Markovnikov's rule as:

$C H_{3} - C H = C H_{2} + H C l ⟶ C H_{3} - C | C l H - C H_{3}$

Thus $C \Rightarrow C H_{3} - C | C l H - C H_{3}$
Alkyl halide with aq. KOH will undergo substitution reaction. Since KOH is a strong base, it will follow $S_{N} 2$ meachanism and will substitute Cl with OH as

$C H_{3} - C | C l H - C H_{3} + a q . K O H \to C H_{3} - C | O H H - C H_{3}$
Thus A is $C H_{3} C H_{2} C H_{2} O H$

and D is $C H_{3} - C | O H H - C H_{3}$
A and D are position isomers.

Suggest Corrections

Similar questions

A compound 'X' reacts with conc. Sulphuric acid to give an alkene. The alkene reacts with bromine and subsequent treatment of the product with alcoholic KOH yields propyne. The formula of the compound is

Q. Primary alkyl halide (a)

C_{4} H_{9} B r

reacted with alcoholic KOH to give compound (b). Compound (b) is reacted with HBr to give (c) which is an isomer of (a). When (a) was reacted with sodium metal it gave a compound (d)

C_{8} H_{18}

that was different than the compound when n-butyl bromide was reacted with sodium. Give the structural of (a) and write the equation for all the reactions.

An organic compound (A) (molecular formula C₈H₁₆O₂) was hydrolysed with dilute sulphuric acid to give a carboxylic acid (B) and an alcohol (C). Oxidation of (C) with chromic acid produced (B). (C) on dehydration gives but-1-ene.Write equations for the reactions involved.

Q. Pyrolusite on heating with

K O H

in presence of air gives a dark green compound (A). The solution of (A) on treatment with sulphuric acid gives a purple colour compound (B). Compound (B) with concentrated

H_{2} S O_{4}

gives (C) which can decompose to (D) and

O_{2}

. What is the number of unpaired electrons in the cation of (D)?

An organic compound A (molecular formula $C_{2} H_{4} O_{2})$ reacts with Na metal to form a compound B and evolves a gas which burns with a pop sound. Compound A on treatment with an alcohol C in the presence of a little of concentrated sulphuric acid forms a sweet-smelling compound D (molecular formula $C_{2} H_{6} O_{2})$ . Compound D on treatment with NaOH solution gives back B and C. Indentity A, B, C and D.

Join BYJU'S Learning Program

A primary alcohol, C3H8O(A) on heating with sulphuric acid undergo dehydration to give an alkene, B. B, when reacted with HCl, gave C, which on treatment with aqueous KOH gives compound D(C3H8O).A and D are:

A primary alcohol, $C_{3} H_{8} O (A)$ on heating with sulphuric acid undergo dehydration to give an alkene, B. B, when reacted with $H C l$ , gave C, which on treatment with aqueous KOH gives compound $D (C_{3} H_{8} O)$ .
A and D are: