A prime number x greater than 100 leaves a remainder y on division by 26. How many values can y take?
9
The number can be written in the form x = 26n + y , where n is a natural number .
If y = 1 , x can be 53 ( n =2 )
y = 2
x = 2(23n + 1) , which is not a prime number.
y = 3 , x can be 29 ( n=1 )
If y = 4
x = 2(23n+2) which is not a prime number.
So y = 1, 3,5,7,9,11,17,21,23 satisfies the condition.