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Question

A prism having refractive index μ=1.53 is placed in water having refractive index μ=1.33. If the angle of prism is 60. Calculate the angle of minimum deviation in water.
(sin35.1=0.575)


A
35.1
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B
30
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C
10.2
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D
20.4
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Solution

The correct option is C 10.2
Given:
μp=1.53; μw=1.33; A=60

Using Snell's law,

μwsini=μpsinr

sinisinr=μpμw ........(1)

For minimum deviation, we know

i=(δmin+A2) and r=A/2

Putting the value in eq. (1), we get

sin(δmin+A2)sin30=1.531.33

sin(δmin+A2)=1.15×12=0.575

δmin+A2=sin1(0.575)=35.1

δmin=2×35.1A=70.260

δmin=10.2

Hence, option (c) is correct.

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