Question

A prism of angle $A=1^{\circ }$ has a refractive index $\mu =1.5$. A good estimate for minimum angle of deviation (in degrees) is close to $\frac{N}{10}$. Value of $N$ is

Answer 1

Given,
Angle of prism, $A=1^{\circ }$
Refractive index of prism, $\mu =1.5$
For a thin prism, minimum angle of deviation is given by
$\Rightarrow \delta =(\mu -1)A$
$\Rightarrow \delta =(1.5-1)\times 1^{\circ }=\frac{1}{2}=\frac{5}{10}$
$\Rightarrow N=5$