A prism of refracting angle $4^{0}$ is made of a material of refractive index $1.6452$ . Its angle of minimum deviation is

{2.708}^{0}

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{4.608}^{0}

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{1.608}^{0}

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{2.608}^{0}

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Solution

The correct option is D ${2.608}^{0}$
$A = 4^{0}, μ = 1.6452, δ = ?$
Substituting in:
$δ = A (μ - 1)$
$= 4^{0} (1.652 - 1)$
$= 4^{0} \times 0.652 = {2.608}^{0}$

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A prism of refracting angle 40 is made of a material of refractive index 1.6452. Its angle of minimum deviation is

The correct option is D 2.6080A=40,μ=1.6452,δ=?Substituting in:δ=A(μ−1) =40(1.652−1) =40×0.652=2.6080

A prism of refracting angle $4^{0}$ is made of a material of refractive index $1.6452$ . Its angle of minimum deviation is

The correct option is D ${2.608}^{0}$
$A = 4^{0}, μ = 1.6452, δ = ?$
Substituting in:
$δ = A (μ - 1)$
$= 4^{0} (1.652 - 1)$
$= 4^{0} \times 0.652 = {2.608}^{0}$