Question

A prismatic steel bar of 30 mm diameter and 600 mm in length fractures at a torque of 1600 N-m. What is the modulus of rupture of this steel in torsion ?

• A. 301.80 MPa
• B. 296 MPa
• C. 125 MPa
• D. 450 MPa

Answer 1

The correct option is A 301.80 MPa

Modulus of rupture = ${\tau }_{ut}$

$\therefore {\tau }_{ut}=\tau =\frac{16T}{\pi d^3}=\frac{16\times 1600\times {10}^3}{\pi \times {30}^3}$

= 301.80 MPa