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Standard XII

Chemistry

Spontaneity

A process has...

Question

A process has $Δ H = 200 J m o l^{- 1}$ and $Δ S = 40 J K m o l^{- 1}$ . Out of the values given above which the process will be sponteneous:

5 K

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4 K

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20 K

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12 K

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Solution

The correct option is A $5 K$
$Δ G = Δ H - T Δ S < 0$
$T = \frac{Δ H}{Δ S} = \frac{200}{40} = 5 K$

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A process has ΔH=200Jmol−1 and ΔS=40JKmol−1. Out of the values given above which the process will be sponteneous:

The correct option is A 5KΔG=ΔH−TΔS<0T=ΔHΔS=20040=5K

A process has $Δ H = 200 J m o l^{- 1}$ and $Δ S = 40 J K m o l^{- 1}$ . Out of the values given above which the process will be sponteneous:

The correct option is A $5 K$
$Δ G = Δ H - T Δ S < 0$
$T = \frac{Δ H}{Δ S} = \frac{200}{40} = 5 K$