Question

A product is an assemble of 5 different components. The product can be sequentially assembled in two possible ways. If the 5 components are placed in a box and these are drawn at random fromt he box, then the probability of getting a correct sequence is

• A. $\frac{2}{5!}$
• B. $\frac{2}{5}$
• C. $\frac{2}{(5-2)!}$
• D. $\frac{2}{(5-3)!}$

Answer 1

The correct option is A $\frac{2}{5!}$

5 components can be arranged by 5! = 120 ways
But Favourable ways to assemble product = 2 (given)
So product can be assembled only when we draw correct sequence.

So P (correct sequence) $=\frac{2}{120}=\frac{2}{5!}$