A progressive wave is represented by $y = 0.5 c o s (5 x - ω t)$ . When it superimposes on another wave a node is formed at $x = 0$ The equation of the second wave is

y = - 0.5 c o s (5 x - ω t)

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y = - 0.5 s i n (5 x - ω t)

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y = 0.5 s i n (5 x + ω t)

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y = - 0.5 c o s (5 x + ω t)

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Solution

The correct option is D $y = - 0.5 c o s (5 x + ω t)$
As a node is formed at $x = 0$ , the equation of the reflected wave should be $y = - 0.5 c o s (5 x + ω t)$

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Similar questions

y = 0.5 c o s (5 x - ω t)

y = α c o s (k x - ω t)

A wave represented by the given equation y = a cos ( kx - $ω$ t ) is superposed

with another wave to form a stationary wave such that the point x = 0 is a

node. The equation for the other wave is

AIIMS 1998; SCRA 1998; MP PET 2001; KCET 2001;

AIEEE 2002; UPSEAT 2004]

y = a cos (k x - ω t)

Y = A c o s (k x - ω t)

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