A progressive wave moves with a velocity of $36 m / s$ in a medium with a frequency of $200 H z$ . The phase difference between two particles separated by a distance of $1 c m$ is:

40

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20

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\frac{π}{9}

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\frac{π}{16}

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Solution

The correct option is C $\frac{π}{9}$
Solution we have, $V = 36 m / s, f = 200 H_{2}$ and
$Δ x = 1 c m = 10^{- 2} m$
we know that,
$v = f λ$
$\Rightarrow λ = \frac{v}{f} = \frac{36}{200} = \frac{9}{50} m$
Also, $Δ ϕ = 2 π (\frac{Δ x}{λ})$
$\Rightarrow Δ ϕ = 2 π \frac{(\frac{1}{100})}{\frac{9}{50}} \Rightarrow Δ ϕ = \frac{π}{4}$
Option - c is correct

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A progressive wave moves with a velocity of 36m/s in a medium with a frequency of 200Hz. The phase difference between two particles separated by a distance of 1cm is:

The correct option is C π9 Solution we have, V=36m/s,f=200H2 and Δx=1cm=10−2mwe know that,v=fλ⇒λ=vf=36200=950mAlso, Δϕ=2π(Δxλ)⇒Δϕ=2π(1100)950⇒Δϕ=π4Option - c is correct

A progressive wave moves with a velocity of $36 m / s$ in a medium with a frequency of $200 H z$ . The phase difference between two particles separated by a distance of $1 c m$ is: