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Standard XII

Physics

Applications of Horizontal and Vertical Components

A projectile ...

Question

A projectile A is projected from ground. An observer B running on ground with uniform velocity of magnitude 'v' observed A to move along a stralight. The time of fight of A as move measured by B is T . Then the range projectile on ground is

R =v T

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R < vT

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R > vT

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R+vT

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Solution

The correct option is A R =v T
observer B seen projectile A travelling in straight vertical path.
$\Rightarrow$ Their relative horizontal velocity is o.
$∴$ Horizontal component of projective = V. ( = speed of observer)
as time of fight is T, the Range is than R = VT.

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A projectile A is projected from ground. An observer B running on ground with uniform velocity of magnitude 'v' observed A to move along a stralight. The time of fight of A as move measured by B is T . Then the range projectile on ground is

The correct option is A R =v Tobserver B seen projectile A travelling in straight vertical path.⇒ Their relative horizontal velocity is o.∴ Horizontal component of projective = V. ( = speed of observer)as time of fight is T, the Range is than R = VT.

The correct option is A R =v T
observer B seen projectile A travelling in straight vertical path.
$\Rightarrow$ Their relative horizontal velocity is o.
$∴$ Horizontal component of projective = V. ( = speed of observer)
as time of fight is T, the Range is than R = VT.