MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Horizontal and Vertical Components of Projectile Motion

A projectile ...

Question

A projectile fired from the top of a $40 m$ high cliff with an initial speed of $50 m / s$ at an unknown angle. Find its speed when it hits the ground. $(g = 10 {m / s}^{2})$

Open in App

Solution

by conservation of energy
$m g 40 + \frac{m 50^{2}}{2} = \frac{m v^{2}}{2}$
on solving we get
$v = 10 \sqrt{33}$ m/s

Suggest Corrections

thumbs-up

0

Similar questions

Q. A projectile is fired from the top of a

40 m

high cliff with an initial speed of

50 m / s

at an unknown angle. Find its speed when it hits the ground.

A projectile is fired from the top of a 40 m high cliff with an initial speed of 50 m/s at an unknown angle. Find its speed when it hits the ground

Q. A projectile is fired from the top of a cliff of height

1000 m

with a speed of

40 m s^{- 1}

at an unknown angle. The speed of projectile when it hits the ground is (take

g = 10 m s^{- 2}

, Neglect air friction)

Q. A body is projected downwards at an angle of

30^{o}

with the horizontal from the top of a building of height

300 m

. Its initial speed is

40 m / s

. Time taken by it to hit the ground is

(g = 10 m / s^{2}

)

Q. A projectile is fired with an initial speed of

{500 m s}^{- 1}

horizontally from the top of a cliff of height 19.6m. At what distance from the foot of the cliff does it strike the ground?

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Falling Balls in Disguise

PHYSICS

Watch in App

explore_more_icon

Explore more

Horizontal and Vertical Components of Projectile Motion

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon