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Derivation of Position-Time Relation by Graphical Method

A projectile ...

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A projectile having initial velocity 20 m/s making an angle 30 degree with vertical.When it makes 45 degree with vertical in upward journey ,then speed becomes

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Q. a projectile is thrown in the upward direction making an angle of 60 degree with the horizontal direction with a velocity of 147 metre per second then the time after which its inclination with the horizontal becomes 45 degree is ????

My thinking:
Uy= 147sin(60) and. Vy= 147sin(45)
Using Vy=Uy-gt
What is wrong in my thinking. ?????

Q. Find the average velocity of a projectile between the instances it crosses one third the maximum height. It is projected with an initial velocity

u

making an angle

θ

with the vertical.

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Derivation of Position-Time Relation by Graphical Method

Standard IX Physics

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