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Byju's Answer

Standard XII

Physics

Non Uniform Motion & Avg Velocity

A projectile ...

Question

A projectile is fired at $30^{o}$ to the horizontal, The vertical component of its velocity is $80 m s^{- 1}$ , Its time flight is T. What will be the velocity of projectile at $t = \frac{T}{2} ?$

80

m s^{- 1}

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80 \sqrt{3}

m s^{- 1}

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\frac{80}{\sqrt{3}}

m s^{- 1}

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40

m s^{- 1}

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Solution

The correct option is B $80 \sqrt{3}$ $m s^{- 1}$
At $t = \frac{T}{2}$ , the velocity of projectile $(v)$ = Horizontal component of its velocity $(v_{x})$
But, $v_{x} = \frac{v_{y}}{tan θ} = \frac{80}{tan 30^{0}}$

$\Rightarrow v = 80 \sqrt{3} m / s$
Therefore, B is correct option.

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Similar questions

A projectile is fired at $30^{\circ}$ to the horizontal. The vertical component of its velocity is $80 m s^{- 1}$ . Its time of flight is T. What will be the velocity of the projectile at $t = \frac{T}{2}$

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A projectile is fired at 30o to the horizontal, The vertical component of its velocity is 80ms−1, Its time flight is T. What will be the velocity of projectile at t=T2?

The correct option is B 80√3 ms−1At t=T2, the velocity of projectile(v) = Horizontal component of its velocity(vx)But, vx=vytanθ=80tan300⇒v=80√3m/sTherefore, B is correct option.

A projectile is fired at $30^{o}$ to the horizontal, The vertical component of its velocity is $80 m s^{- 1}$ , Its time flight is T. What will be the velocity of projectile at $t = \frac{T}{2} ?$

The correct option is B $80 \sqrt{3}$ $m s^{- 1}$
At $t = \frac{T}{2}$ , the velocity of projectile $(v)$ = Horizontal component of its velocity $(v_{x})$
But, $v_{x} = \frac{v_{y}}{tan θ} = \frac{80}{tan 30^{0}}$

$\Rightarrow v = 80 \sqrt{3} m / s$
Therefore, B is correct option.