Question

A projectile is fired from ground to have maximum range of 600 m. Maximum height attained by the projectile in this case will be

• A. $1200m$
• B. $600m$
• C. $150m$
• D. $125m$

Answer 1

The correct option is C $150m$

Given,

$R_{max}=600m$

Horizontal range in projectile motion is given by

$R=\frac{u^{2}sin2\theta }{g}$

For maximum range, $\theta ={45}^0$

$R_{max}=\frac{u^{2}sin{90}^0}{g}$

$600=\frac{u^2}{g}$

$u=600g$

The maximum height attained by the projectile,

$H=\frac{u^{2}si{n}^2\theta }{2g}$

$H=\frac{600g\times si{n}^2{45}^0}{2g}$

$H=300\times \frac{1}{2}$

$H=150m$

The correct option is C.