wiz-icon
MyQuestionIcon
MyQuestionIcon
8
You visited us 8 times! Enjoying our articles? Unlock Full Access!
Question

A projectile is fired from the top of a 40 m height cliff with an initial speed of 50 m/s at an unknown angle. Find its speed when it hits the ground.

A
48 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
56 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
58 m/s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
68 m/s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 58 m/s
Given data, height of the cliff, h=40 m
Initial speed of the projectile, u=50 m/s
Let the projectile hit the ground with velocity v
Applying the law of conservation of energy,
mgh+12mu2=12mv2
10×40+12×2500=12v2
v2=3300
v=57.4 m/s=58 m/s

flag
Suggest Corrections
thumbs-up
22
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
The Law of Conservation of Mechanical Energy
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon