A projectile is fired from the top of a 40m height cliff with an initial speed of 50m/s at an unknown angle. Find its speed when it hits the ground.
A
48m/s
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B
56m/s
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C
58m/s
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D
68m/s
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Solution
The correct option is C58m/s Given data, height of the cliff, h=40m Initial speed of the projectile, u=50m/s Let the projectile hit the ground with velocity ′v′ Applying the law of conservation of energy, mgh+12mu2=12mv2 10×40+12×2500=12v2 v2=3300 v=57.4m/s=58m/s