A projectile is fired from the top of a cliff of height 1000m with a speed of 40msā1 at an unknown angle. The speed of projectile when it hits the ground is (take g=10msā2, Neglect air friction)
A
60ms−1
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B
40ms−1
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C
100ms−1
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D
200ms−1
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Solution
The correct option is A60ms−1
Applying conservation of energy principle, [A→B] Ui+Ki=Uf+Kf⇒12m[40]2+mg[1000]=12mv2+0⇒800m+1000m=12mv2⇒v2=3600⇒v=60ms−1