wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A projectile is fired horizontally with a speed of 98ms−1 from the top of a hill 490m high. Find the time taken to reach the ground.

A
5s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
10s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
15s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
20s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 10s
Answer is B.
The projectile is fired from the top O of a hill with speed u = 98ms1 along the horizontal as shown as OX. It reaches the target P at vertical depth OA, in the coordinate system as shown, OA=y=490m

As, y=12gt2

490=12×9.8t2

or .t=100=10s

Hence, the time taken to reach the ground is 10s.

315053_300060_ans_0cf216381c6c4445badaa1164aeec605.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Falling Balls in Disguise
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon