Question

A projectile is fired horizontally with a velocity of $98m/s$ from the top of a hill $490m$ high. Find the time taken by the projectile to reach the ground.

Answer 1

Given : $u_x=98m/s$ $a_y=g=9.8m/s^2$

Height of the hill $S_y=h=490$ m

$\therefore$ Time of flight $T=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2\left(490\right)}{9.8}}=10$ s