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Question

A projectile is fired with a constant speed at two different angles of projection, say α and β, that give it the same range. Then, α and β are such that,

A
cosecα=secβ
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B
tan(α+β)
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C
sin2αcos2α=sin2βcos2β
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D
sin2α+cos2α=sin2β+cos2β
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Solution

The correct options are
A cosecα=secβ
B tan(α+β)
D sin2α+cos2α=sin2β+cos2β
For the same range, α+β=90 (or ) β=90α. Choices a), b) and d) are correct as they satisfy these relations.

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