Question

A projectile is fired with a velocity $V=3\sqrt{2}$ m/s from a point at height H = 0.8 m at an angle of 45${}^o$ with respect to the horizontal direction as shown in the Figure. Find the horizontal distance S in meters travelled by the projectile when it hits the ground. Take acceleration due to gravity as 10 m/s${}^2$.__________

• A. 2.4

Answer 1

The correct option is A 2.4
$v=3\sqrt{2}m/sec$

$v_y=vsin45=3m/sec$

$v_x=vcos45=3m/sec$

$h=0.8m$

Taking upward as positive and downward negative.

$h=v_{y}t-\frac{1}{2}g{t}^2$

$-0.8=3t-\frac{1}{2}\times 10\times t^2\Rightarrow t=0.8$

$x=v_{x}t=3\times 0.8=2.4m$