wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A projectile is fired with some velocity making certain angle with the horizontal. Which of the following graphs is the best representation for the kinetic energy of a projectile (KE) versus its horizontal displacement (x)?

A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D
Let the velocity of projectile be u and projection angle be θ, then
Horizontal velocity =ucosθ
Velocity along vertical direction =usinθgxucosθ

So, velocity of a projectile at any instant of time (t) is
v2=v2x+v2y=(ucosθ)2+(usinθgxucosθ)2
v2=u2cos2θ+u2sin2θ+g2x2u2cos2θ2gxtanθ
KE=12mv2=12mu2mgxtanθ+mg2x2u2cos2θ
The given equation represents the equation of a parabola.
Note: Answer cannot be (b) as KE of a projectile never becomes zero.

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Falling Balls in Disguise
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon