A projectile is given an initial velocity of -2- m-s- where - is along the ground and - is along the vertical- If g-10 m-s2- the equation of its trajectory is-

The correct option is C y=2x 5x^2 u⃗ = î + 2ĵ; ∴ u cosθ = 1; u sinθ =2 x=u cosθ t =t y=u sinθ t 12gt^2 = 2t 5t^2 Substituting t ...

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Byju's Answer

Standard XII

Physics

The Equation for the Path of Projectile

A projectile ...

Question

A projectile is given an initial velocity of $(^i + 2^j) m / s$ , where $^i$ is along the ground and $^j$ is along the vertical. If $g = 10 m / s^{2}$ , the equation of its trajectory is:

y = 2 x - 5 x^{2}

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4 y = 2 x - 5 x^{2}

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4 y = 2 x - 25 x^{2}

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y = x - 5 x^{2}

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Solution

The correct option is C $y = 2 x - 5 x^{2}$
$\to u =^i + 2^j;$
$∴ u cos θ = 1; u sin θ = 2$
$x = u cos θ t = t$
$y = u sin θ t - \frac{1}{2} g t^{2} = 2 t - 5 t^{2}$
Substituting $t = x$
Equation of trajectory is $y = 2 x - 5 x^{2}$

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A projectile is given an initial velocity of ( $^i$ +2 $^j$ ) $\frac{m}{s}$ , where $^i$ is along the ground and $^j$ is along the vertical. If g = 10 $\frac{m}{s^{2}}$ , the equation of its trajectory is:

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A projectile is given an initial velocity of (^i+2^j) m/s, where ^i is along the ground and ^j is along the vertical. If g=10 m/s2, the equation of its trajectory is:

The correct option is C y=2x−5x2→u=^i+2^j;∴ucosθ=1;usinθ=2x=ucosθt=ty=usinθt−12gt2=2t−5t2Substituting t=xEquation of trajectory is y=2x−5x2

A projectile is given an initial velocity of $(^i + 2^j) m / s$ , where $^i$ is along the ground and $^j$ is along the vertical. If $g = 10 m / s^{2}$ , the equation of its trajectory is:

The correct option is C $y = 2 x - 5 x^{2}$
$\to u =^i + 2^j;$
$∴ u cos θ = 1; u sin θ = 2$
$x = u cos θ t = t$
$y = u sin θ t - \frac{1}{2} g t^{2} = 2 t - 5 t^{2}$
Substituting $t = x$
Equation of trajectory is $y = 2 x - 5 x^{2}$