Question

A projectile is moving at 20 m/s at its highest point, where it breaks into equal parts due to an internal explosion. One part moves vertically up at 30 m/s with respect to he ground. Then the other part will move at:

• A. $20m/s$
• B. $10\sqrt{13}m/s$
• C. $50m/s$
• D. $30m/s$

Answer 1

Answer: (C)

$50m/s$

Using momentum conservation,
$m\times 20\hat{i}=m/2\times 30\hat{j}+m/2\times x$
$x=40\hat{i}-30\hat{j}$

$\Rightarrow |x|=50$.