A projectile is projected with a linear momentum ′p′ making an angle θ with the horizontal. The change in momentum of the projectile on return to the ground will be :
A
2pcotθ
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B
2psinθ
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C
2pcosθ
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D
Remains unchanged
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Solution
The correct option is B2psinθ |(Pt−Pi)|=Change in momentum =√P2+P2+2P⋅Pcos(π−2θ) =P√2+2(−cos2θ) =P√2(2sin2θ) =2Psinθ.