A projectile is projected with initial velocity 6- - 8- ms-1- If g - 10 ms-2- then horizontal range is

The correct option is A 4.8 metreHere, u_x = 6 and u_y = 8 R = 2u_xu_yg = 2× 6× 810 = 9.6 m . ...

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Work Energy Theorem Application

A projectile ...

Question

A projectile is projected with initial velocity $(6^i + 8^j) m s^{- 1}$ . If $g = 10 m s^{- 2}$ , then horizontal range is

4.8

metre

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9.6

metre

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19.2

metre

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14.0

metre

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A projectile is projected with initial velocity $(6^i + 8^j) m / s e c . I f g = 10 m s^{- 2}$ , then horizontal range is

(6^i + 8^j) m s^{- 1}

(g = 10 m / s^{2})

x = 4 t

y = 3 t - 4 t^{2}

(6^i + 8^j)

g = 10

m s^{- 2}

1000

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