A projectile is required to hit a target whose co-ordinates relative to horizontal and vertical axes through the point of projection are - - If the gun velocity is -2 g - Then the condition when it is impossible to hit the target-A- 3 -4 - 4 -3 - 3 -4 -D- 4 -3 -

The correct options are B 4β gt;3α β=α tan θ 1/2gα^2/u^2cos^2θ β=α tan θ 1/2gα^2/2gα(1+tan^2θ) tan^2θ 4tanθ+(1+4β/α )=0 If particle will not hit the target. ...

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Byju's Answer

Standard XII

Physics

Throwing and Catching at Same Height

A projectile ...

Question

A projectile is required to hit a target whose co-ordinates relative to horizontal and vertical axes through the point of projection are $(α, β)$ . If the gun velocity is $\sqrt{2 g α}$ . Then the condition when it is impossible to hit the target.

$3 α > 4 β$

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$4 β > 3 α$

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$3 β > 4 α$

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$4 α > 3 β$

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Solution

The correct option is B
$4 β > 3 α$

$β = α t a n θ - \frac{1}{2} g \frac{α^{2}}{u^{2} c o s^{2} θ} β = α t a n θ - \frac{1}{2} g \frac{α^{2}}{2 g α} (1 + t a n^{2} θ) t a n^{2} θ - 4 tan θ + (1 + \frac{4 β}{α}) = 0$

If particle will not hit the target.

$(b^{2} - 4 a c) < 0 16 - 4 (1 + \frac{4 β}{α}) < 0 4 β > 3 α$

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A projectile is required to hit a target whose co-ordinates relative to horizontal and vertical axes through the point of projection are (α,β). If the gun velocity is √2gα. Then the condition when it is impossible to hit the target.

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A projectile is required to hit a target whose co-ordinates relative to horizontal and vertical axes through the point of projection are $(α, β)$ . If the gun velocity is $\sqrt{2 g α}$ . Then the condition when it is impossible to hit the target.