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Standard XII

Physics

Relation between Work Done and PE

A projectile ...

Question

A projectile is thrown from a point in a horizontal place such that its horizontal and vertical velocity component are 9.8 m/s and 19.6 m/s respectively. Its horizontal range is

4.9 m

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9.8 m

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19.6 m

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39.2 m

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Solution

The correct option is D
39.2 m

We know $R = \frac{2 u_{x} u_{y}}{g} = \frac{2 \times 9.8 \times 19.6}{9.8} = 39.2 m$

Where $u_{x}$ = horizontal component of initial velocity, $u_{y}$ = vertical component of initial velocity.

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A projectile is thrown from a point in a horizontal place such that its horizontal and vertical velocity component are 9.8 m/s and 19.6 m/s respectively. Its horizontal range is

The correct option is D 39.2 m We know R=2uxuyg=2×9.8×19.69.8=39.2m Where ux = horizontal component of initial velocity, uy= vertical component of initial velocity.

The correct option is D
39.2 m

We know $R = \frac{2 u_{x} u_{y}}{g} = \frac{2 \times 9.8 \times 19.6}{9.8} = 39.2 m$

Where $u_{x}$ = horizontal component of initial velocity, $u_{y}$ = vertical component of initial velocity.