A projectile is thrown from the base of an incline of 30∘ as shown in the figure. It is thrown at an angle of 60∘ from the horizontal direction at a speed of 10m/s. The total time of flight is: (g=10m/s2)
A
2√3s
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B
√32s
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C
√3s
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D
0.5s
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Solution
The correct option is A2√3s The relation of time of flight for a projectile on an inclined plane is given by, T=2usin(θ−α)gcosα
Now, θ=60∘, α=30∘, u=10m/s. Putting these values, we get T=2×10sin(60∘−30∘)gcos30∘ ⇒T=20sin30∘10×cos30∘=2√3s