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General Gravity Problem

A projectile ...

Question

A projectile is thrown horizontally with a speed of $20 m s^{- 1}$ . If g is $10 m s^{- 2}$ , then the speed of the projectile after $5$ second will be nearly

0.5 m s^{- 1}

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5 m s^{- 1}

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54 m s^{- 1}

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500 m s^{- 1}

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Solution

The correct option is C $54 m s^{- 1}$
Velocity is x direction is not changed because there is no acceleration in x. Thus $v_{X}$ will remain $20 m / s$ .
$v_{Y} = u_{Y} - g t = 0 - 10 \times 5 = - 50 m / s$
Thus, $S p e e d = \sqrt{v_{X}^{2} + v_{Y}^{2}} = \sqrt{400 + 2500} = \sqrt{2900} \approx 54 m s^{- 1}$

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