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Question

A projectile is thrown horizontally with a speed of 20 m s−1. If g is 10 ms−2, then the speed of the projectile after 5 seconds will be nearly

A
0.5 ms1
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B
5 ms1
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C
54 ms1
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D
500 ms1
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Solution

The correct option is C 54 ms1
Let v be the velocity of the projectile after 5 sec.
Even after 5 seconds, the horizontal velocity vx will be 20 ms1 as there is no acceleration along horizontal direction.
The vertical velocity vy is given by
vy=uy+gt
(Take downward direction as positive)
uy=0 ( there is no initial velocity in the vertical direction)
vy=0+10×5=50 ms1
So, speed after 5 sec
v=v2x+v2y=202+50254 ms1

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