A projectile is thrown horizontally with a speed of 20m s−1. If g is 10ms−2, then the speed of the projectile after 5 seconds will be nearly
A
0.5ms−1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
5ms−1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
54ms−1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
500ms−1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C54ms−1 Let v be the velocity of the projectile after 5 sec. Even after 5 seconds, the horizontal velocity vx will be 20ms−1 as there is no acceleration along horizontal direction. The vertical velocity vy is given by vy=uy+gt (Take downward direction as positive) uy=0 ( ∵ there is no initial velocity in the vertical direction) ⇒vy=0+10×5=50ms−1 So, speed after 5sec v=√v2x+v2y=√202+502≈54ms−1