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Question

A projectile is thrown in the upward direction making an angle of 60o with the horizontal direction with a velocity of 147 ms1. Then the time after which its inclination with the horizontal is 45o, is?

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Solution

Vy /Vx =tan45 or Vy =Vx
Vx remains constant =147cos60

Vy now using equation of motion for verticle direction

Vy=Uy-gt

Uy=147sin60

Uy=147cos60

putting in eq 1

t=5.36 sec


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