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Question

A projectile is thrown with velocity u making angle θ with the vertical. It just crosses the top of two poles each of height h after 1 sec and 3 sec respectively. The maximum height of projectile is

A
9.8 m
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B
19.6 m
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C
39.2 m
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D
4.9 m
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Solution

The correct option is B 19.6 m

The projectile is at height h at times 1 sec and 3 sec, means the total time of projectile is 4 sec, since it takes the same 1 sec to reach ground after that 3 secs.

So it will be at Maximum height at time t = 2 sec

H=12gt2
H=12×9.8×2×2
H = 19.6 m

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