A projectile of mass $0.5 k g$ is thrown with a velocity of $30 m / s$ at an angle of $60^{0}$ with the horizontal. Find its momentum at highest point.

7.5 N - s

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9 N - s

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5.5 N - s

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12 N - s

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Solution

The correct option is A $7.5 N - s$
At the highest point y-component of velocity becomes $0$

So, the x-component of velocity is the net velocity.

Finding x-component of velocity
$u c o s θ = 30 c o s 6 0^{0} = 15 m / s$ .

So, the velocity at the highest point is $15 m / s$ .

Hence $p = m \times v$
$p = 0.5 \times 15 = 7.5 N - s$

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