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Question

A projectile of mass 0.5 kg is thrown with a velocity of 30 m/s at an angle of 600 with the horizontal. Find its momentum at highest point.

A
7.5 Ns
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B
9 Ns
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C
5.5 Ns
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D
12 Ns
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Solution

The correct option is A 7.5 Ns
At the highest point y-component of velocity becomes 0

So, the x-component of velocity is the net velocity.

Finding x-component of velocity
u cosθ=30 cos 600=15 m/s.

So, the velocity at the highest point is 15 m/s.

Hence p=m×v
p=0.5×15=7.5 Ns

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