A projectile of mass 3 kg is projected with velocity 10 m - s at an angle 53- with horizontal- At the top of its trajectory it explodes into two fragments in the mass ratio 1- 2- Lighter fragment retraces its path- g -10 m - s 2A- Heavier fragment fall at distance 7-2 m from point of projectionB- Heavier fragment fall at distance 14-4 m from point of projectionC- Energy released in explosion is 100 J-D- Energy released in explosion is 108 J-

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Standard XII

Physics

Conservation of Momentum

A projectile ...

Question

A projectile of mass 3 kg is projected with velocity 10 m/s at an angle $53^{\circ}$ with horizontal. At the top of its
trajectory it explodes into two fragments in the mass ratio 1 : 2. Lighter fragment retraces its path. $(g = 10 m / s^{2})$

Heavier fragment fall at distance 7.2 m from point of projection

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Heavier fragment fall at distance 14.4 m from point of projection

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Energy released in explosion is 100 J.

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Energy released in explosion is 108 J.

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Solution

The correct options are
B Heavier fragment fall at distance 14.4 m from point of projection
D Energy released in explosion is 108 J.
Centre of mass is not effected by internal forces that causes explosion. so, $m_{1} x_{1} = m_{2} x_{2}$
$1 (\frac{R}{2}) = 2 x_{2}$
$X_{2} = (\frac{R}{4})$ from center
And from point of projection it is $(\frac{3 R}{4})$
R is range of unexploded projectile.

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A projectile of mass 3 kg is projected with velocity 10 m/s at an angle 53∘ with horizontal. At the top of its trajectory it explodes into two fragments in the mass ratio 1 : 2. Lighter fragment retraces its path. (g=10m/s2)

A projectile of mass 3 kg is projected with velocity 10 m/s at an angle $53^{\circ}$ with horizontal. At the top of its
trajectory it explodes into two fragments in the mass ratio 1 : 2. Lighter fragment retraces its path. $(g = 10 m / s^{2})$