wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A projectile of mass 50 kg is shot vertically upwards with a velocity of 100 m/s. After 5 seconds the projectile explodes into two fragments, one of which (mass 20 kg) travels vertically up with a velocity of 150 m/s. What will be the velocity of the other fragment at this moment? (g=9.8m/s2)

Open in App
Solution

Initial velocity = 100 m/s

Velocity after 5 second :

V = u + at

V = 100 - 9.8 ( 5 )

V = 51 m/s

According to the law of conservation of linear momentum,

initial momentum = final momentum

MV = M1V1+M2V2

M = 50 kg

M1 = 20 kg

M2 = 30 kg

V1= 150 m/s

on substituting the value ,

We get.

V2=15m/s

negative sing signifies that other fragment is moving downward

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon