A projectile of mass 50 kg is shot vertically upwards with an initial velocity of 100m/s . After 5 seconds it explodes into two fragments, one of which having mass 20 kg, travels vertically up with a velocity of $150 m s^{- 1}$ . The velocity of the other fragment at that instant is

- 70 m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 70 / 3 m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 50 m s^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 50 / 3 m s^{- 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $- 50 / 3 m s^{- 1}$
Velocity of $50 k g$ mass after $5 s e c$

$\frac{v - μ}{t} = g$

$\frac{v - 100}{5} = - 10$

$v = 50 m / s$
using momentum conservation at explosion
$50 \times 50 = 20 \times 150 + 30 \times v$
$2500 - 3000 = 30 \times v$

$\Rightarrow \frac{- 500}{30} = - 16.67 m / s$

Suggest Corrections

Similar questions

Q. A projectile of mass 4 kg is fired with a velocity 4 m/s at an angle

45^{0}

with the horizontal. At the highest position in its flight, it explodes into two fragments of masses 1 kg and 3 kg. The heavier fragment falls vertically with zero initial speed. the horizontal distance between the fragments when they touch the ground is

A projectile of mass 50 kg is projected vertically upward with a velocity of 100 m/s. After 5 seconds it explodes into two pieces, one piece of 20 kg moving vertically upward with a velocity of 150 m/s. The algebraic sum of the momentum of the system 3 seconds later is

Q. A projectile of mass