1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A projectile of mass m is fired with a velocity u from a point P as shown. Neglecting air resistance, find the magnitude of the change in momentum of the projectile between the points P and Q.

A
musecβsin(αβ)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
musinα(tan β1)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
mu(tanβ1)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
mucosα
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A musecβsin(α−β)In the horizontal direction, velocity is constant. Hence, ucosα=Vcosβ ⇒V=ucosαcosβ(1) In the vertical direction : Δpy=m(VQy−VPy) =m(Vsinβ−usinα) Substituting the value of V from (1), we get Δpy=m(ucosαcosβ×sinβ−usinα) Δpy=musecβ(cosαsinβ−sinαcosβ) Δpy=−musecβsin(α−β) In terms of magnitude, Δpy=musecβsin(α−β)

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program