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Question

A projectile projected from the ground has its direction of motion making an angle π4 with the horizontal at a height 40 m. If initial velocity of projection is 50 m/s, the angle of projection is (take g=10 ms2)


A

12cos1(825)

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B

12cos1(825)

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C

12cos1(45)

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D

12cos1(14)

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Solution

The correct option is A

12cos1(825)


Let projection angle be θ and velocity at 40 m height be 'v'

then, 50 cos θ=v cos 45o

v=502cosθ ............. (1)

Now, v2yu2y=2aysy

(v sin 45o)2(50 sin θ)2=2(10)(40) .........(2)

From (1) and (2)

θ=12cos1(825)


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