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Question

A projectile shot at an angle of 45o above the horizontal strikes a building 30 m away at a point 15 m above the point of projection. Find : (a) the speed of projection. (b) the magnitude and direction of velocity of projectile when it strikes the building

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Solution

y=xtanθo128uo2cos2θox2_____(1)

v2=u22gh

Vertical component of velocity

Vx2=[143× sin45]22×9.8×15

=0

We have only horizontal component

Vy=143 cos45

=17.15ms1 (IMAGE)


1090095_1129919_ans_b5927f593c56474b8c55d413b207597d.PNG

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