A projectile thrown with a speed v at an angle - has a range R on the surface of earth-For the same v and - its range on the surface of moon will be -gmoon-gearth6-

A projectile thrown with an initial speed u and angle of projection $15^{\circ}$ to the horizontal has a range R. If the same projectile is thrown at an angle of $45^{\circ}$ to the horizontal with speed 2u, its range will be

Q. A projectile fired with Initial velocity

u

at some angle

θ

has a range

R

. If the initial velocity be doubled at the same angle of' projection. then the range will be

A projectile fired with initial velocity u at some angle $θ$ has a range R. If the initial velocity be doubled at the same angle of projection, then the range will be

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A projectile thrown with a speed v at an angle θ has a range R on the surface of earth.For the same v and θ, its range on the surface of moon will be [gmoon=gearth6]

The correct option is C 6R For Earth, Range is given by, Re=u2sin2θge On moon, Given, gm=ge/6 ∴Rm==u2sin2θgm ∴ReRm=u2sin2θgeu2sin2θgm=gmge=16 ⇒Rm=6Re

A projectile thrown with a speed v at an angle $θ$ has a range R on the surface of earth.For the same v and $θ$ , its range on the surface of moon will be $[g_{m o o n} = \frac{g_{e a r t h}}{6}]$