A projector lamp can be used at a maximum voltage of 60 V, its resistance is 20, the series resistance (in ohms) required to operate the lamp from a 75 V supply is
A
2
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B
3
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C
4
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D
5
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Solution
The correct option is D 5 Vbulb=I×20⇒I=3A ⇒IRmin=15 Rmin=5Ω