Question

A property valued at Rs. 30000 will depreciate Rs. 1380 the first year, Rs. 1340 the second year, Rs. 1300 the third year, and so on. What will the depreciation during the eight year?

• A. Rs. 1150
• B. Rs. 1200
• C. Rs. 1100
• D. Rs. 1250

Answer 1

The correct option is C Rs. 1100

Every year depreciation decrease by 40, so the given problem can be solved through the AP: 1380, 1340, 1300, ........

So $a=1380,d=40,n=8$
$\therefore$ Depreciation during eight year
$=1380+(8-1)\times (-40)=Rs.1100$