A - B 3 and when A -8- B -2If B-4- then find the value of A-A- 16B- 8C- 64D- 32

The correct option is C 64Given, A ∝ B^3 Let the constant of variation be k. ⇒ A = kB^3 Given, at A = 8, B = 2. So, k = A/B^3 = 8/2^3 = 8/8 = 1. Hence, at B ...

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Byju's Answer

Standard VIII

Mathematics

Variation

A ∝ B 3 and w...

Question

$A \propto B^{3}$ and when A = 8, B = 2.
If B = 4, then find the value of A.

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Solution

The correct option is A 64
$G i v e n, A \propto B^{3}$
Let the constant of variation be k.
$\Rightarrow A = k B^{3}$
Given, at A = 8, B = 2.
So, $k = \frac{A}{B^{3}} = \frac{8}{2^{3}} = \frac{8}{8} = 1.$
Hence, at B = 4, the value of $A = k B^{3} = (1) (4^{3}) = 64.$

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A∝ B3 and when A = 8, B = 2. If B = 4, then find the value of A.

The correct option is A 64Given, A∝ B3 Let the constant of variation be k. ⇒A=kB3 Given, at A = 8, B = 2. So, k=AB3 =823=88=1. Hence, at B = 4, the value of A=kB3=(1)(43)=64.

$A \propto B^{3}$ and when A = 8, B = 2.
If B = 4, then find the value of A.

The correct option is A 64
$G i v e n, A \propto B^{3}$
Let the constant of variation be k.
$\Rightarrow A = k B^{3}$
Given, at A = 8, B = 2.
So, $k = \frac{A}{B^{3}} = \frac{8}{2^{3}} = \frac{8}{8} = 1.$
Hence, at B = 4, the value of $A = k B^{3} = (1) (4^{3}) = 64.$