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Question

A proton, a deuteron and an α-particle accelerated through the same potential difference enter a region of uniform magnetic field, moving at right angles to B. What is the ratio of their kinetic energies?

A
2:1:1
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B
2:2:1
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C
1:2:1
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D
1:1:2
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Solution

The correct option is D 1:1:2
Kinetic energy gained by charged particle of charge q when accelerated under a potential difference V will be KE=qV
For a given V,KEq
For proton, deuteron and α-particle the ratio of charges is 1:1:2

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