A proton, a deuteron and an $α$ - particle having same momentum enters a region of uniform magnetic field. Relation between radius of there trajectories is best given by

R_{P} = R_{d} = R_{α}

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R_{p} > R_{d} > R_{α}

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R_{p} = R_{d} > R_{α}

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R_{p} = R_{d} < R_{α}

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Solution

The correct option is C $R_{p} = R_{d} > R_{α}$
Radius of trajectory $R = \frac{m v}{q B} = \frac{P}{q B}$
$R_{p} = \frac{p}{e B}, R_{d} = \frac{p}{e B}, R_{α} = \frac{p}{2 e B}$
$R_{p} = R_{d} > R_{α}$

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A proton, a deuteron and an α - particle having same momentum enters a region of uniform magnetic field. Relation between radius of there trajectories is best given by

The correct option is C Rp=Rd>RαRadius of trajectory R=mvqB=PqB Rp=peB,Rd=peB,Rα=p2eB Rp=Rd>Rα

A proton, a deuteron and an $α$ - particle having same momentum enters a region of uniform magnetic field. Relation between radius of there trajectories is best given by

The correct option is C $R_{p} = R_{d} > R_{α}$
Radius of trajectory $R = \frac{m v}{q B} = \frac{P}{q B}$
$R_{p} = \frac{p}{e B}, R_{d} = \frac{p}{e B}, R_{α} = \frac{p}{2 e B}$
$R_{p} = R_{d} > R_{α}$